finite rank造句
造句與例句
手機(jī)版
- We investigate the relations between certain bases and quasi - bases , prove that a space has finite rank base if and only if it has finite rank quasi - base , a space has an ortho - base if and only if it has an ortho - quasi - base
摘要我們研究了某些基與擬基的關(guān)系，證明了空間具有有限秩的基當(dāng)且僅當(dāng)它有有限秩的擬基，空間具有正交基當(dāng)且僅當(dāng)它有正交的擬基。 - We first present the decomposition of finite rank operators and trace class operators in a weakly closed nest algebra algn - module . secondly , the same question for finite rank operators in the preanm ' hilator of an atomic boolean lattice algebra is considered . ( 6 ) let n be a nest on a hilbert space h . and u be any weakly closed algn - module
在第三章中，我們首先討論了弱閉套代數(shù)模中的有限秩算子和跡類算子的“保跡范數(shù)可加性分解”問題，然后研究了原子boolean格代數(shù)的預(yù)零化子中的有限秩算子，得到( 6 )設(shè)n是hilbert空間h中的一個(gè)套， u是任一弱閉algn -模。 - Then the following state - ments are equivalent : ( 1 ) 0 is an isolated point in ( 2 ) a is a finite rank operator ; is the spectral projector associated with . theorem4 . 5 let a be a compact normal operator , is an isolated point in prop4 . 13 let a be a compact normal operator , ao is an isolated point in a ( a )
定理乏止設(shè)a是緊正常算子，則下列條件等價(jià)： （ ）是o （ a ）的孤立盧、 ；仰a是有限秩算子； w 2n間a二一，其中燦1 ， …為” （用自所有的互不相同的孤立點(diǎn)，民： h ?馬人一川為關(guān)于入的譜投影算子 - It's difficult to see finite rank in a sentence. 用finite rank造句挺難的
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